本文主要是介绍LeetCode - 41. First Missing Positive,希望对大家解决编程问题提供一定的参考价值,需要的开发者们随着小编来一起学习吧!
41. First Missing Positive Problem's Link
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Mean:
给你一组整数,找出第一个空缺的正整数.
要求:时间O(n),空间O(n).
analyse:
这题时间O(n)想了半天没想到,用O(n*logn)过的.
然后看了discuss,想法非常巧妙,自愧不如.
Time complexity: O(N)
view code
* -----------------------------------------------------------------
* Copyright (c) 2016 crazyacking.All rights reserved.
* -----------------------------------------------------------------
* Author: crazyacking
* Date : 2016-03-05-18.56
*/
#include <queue>
#include <cstdio>
#include <set>
#include <string>
#include <stack>
#include <cmath>
#include <climits>
#include <map>
#include <cstdlib>
#include <iostream>
#include <vector>
#include <algorithm>
#include <cstring>
using namespace std;
typedef long long( LL);
typedef unsigned long long( ULL);
const double eps( 1e-8);
class Solution
{
public :
vector < vector < int >> combinationSum2( vector < int >& candidates , int target)
{
sort( candidates . begin (), candidates . end());
vector < vector < int >> res;
vector < int > combination;
combinationSum( candidates , res , combination , target , 0);
return res;
}
private :
void combinationSum( vector < int >& candidates , vector < vector < int >> & res , vector < int >& combination , int target , int begin)
{
if( ! target)
{
res . push_back( combination);
return;
}
for( int i = begin; target >= candidates [ i ] && i < candidates . size() ; ++ i)
{
if( i == begin || candidates [ i ] != candidates [ i - 1 ])
{
combination . push_back( candidates [ i ]);
combinationSum( candidates , res , combination , target - candidates [ i ], i + 1);
combination . pop_back();
}
}
return;
}
};
int main()
{
freopen( "H: \\ Code_Fantasy \\ in.txt" , "r" , stdin);
int n , target;
while( cin >>n >> target)
{
cout <<n << " " << target << endl;
vector < int > ve;
for( int i = 0; i <n; ++ i)
{
int tmp;
cin >> tmp;
ve . push_back( tmp);
}
Solution solution;
vector < vector < int >> ans = solution . combinationSum2( ve , target);
for( auto p1: ans)
{
for( auto p2: p1)
{
cout << p2 << " ";
}
cout << endl;
}
}
return 0;
}
/*
*/
O(n)时间,O(1)空间的代码:
public :
int firstMissingPositive( vector < int >& nums) {
int n = nums . size();
for ( int i = 0; i < n; i ++)
while ( nums [ i ] > 0 && nums [ i ] <= n && nums [ nums [ i ] - 1 ] != nums [ i ])
swap( nums [ i ], nums [ nums [ i ] - 1 ]);
for ( int i = 0; i < n; i ++)
if ( nums [ i ] != i + 1)
return i + 1;
return n + 1;
}
};
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