C++ boost::upgrade_lock boost::upgrade_to_unique_lock如何使用 例子

本文主要是介绍C++ boost::upgrade_lock boost::upgrade_to_unique_lock如何使用 例子，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

upgrade_lock将可将读锁（shared_lock）升级为upgrade_lock，与shared_lock不互斥，与别的upgrade_lock和unique_lock互斥。

也就是说线程A获得mutex的upgrade_lock后，线程B、C等还可以获得mutex的share_mutex，反之亦然。

upgrade_to_unique_lock可将upgrade_lock升级为独占锁，不允许其它线程读或写
 

question

So I had some shared_mutex and done this:

        boost::upgrade_lock<boost::shared_mutex> lock(f->mutex);boost::upgrade_to_unique_lock<boost::shared_mutex> uniqueLock(lock);

now I want to "unlock it" or at least downgrade it to something like:

boost::shared_lock<boost::shared_mutex> lock_r(f->mutex);

How to do such thing? Is it possible?

solution

If you let the upgrade_to_unique_lock go out of scope, it will automatically downgrade back to upgrade ownership.

For example

void foo() {boost::upgrade_lock<boost::shared_mutex> lock(f->mutex);// Do shared operations, as mutex is held upgradeable// ...if(need_to_get_unique){boost::upgrade_to_unique_lock<boost::shared_mutex> uniqueLock(lock); // Do exclusive operations, as mutex is held uniquely// ... // At end of scope unique is released back to upgradeable}// Only shared operations here, as it's only held upgradeable// ...// At end of scope mutex is completely released
}

Edit: One other thing. If a given function only requires exclusive locks, you can use boost::unique_lock and lock uniquely, without going through both the upgrade and upgrade_to_unique locks.

如何解锁boost :: upgrade_to_unique_lock(由boost :: shared_mutex制成)? - IT屋-程序员软件开发技术分享社区

这篇关于C++ boost::upgrade_lock boost::upgrade_to_unique_lock如何使用 例子的文章就介绍到这儿，希望我们推荐的文章对编程师们有所帮助！

---