NumPy（十三）：数组的复制【.copy()】

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import numpy as np# 数组的复制ar1 = np.arange(10)
ar2 = ar1
print('ar1 = {0}, ar2 = {1}'.format(ar1, ar2))
print('ar2 is ar1: ', ar2 is ar1)# 回忆python的赋值逻辑：指向内存中生成的一个值 → 这里ar1和ar2指向同一个值，所以ar1改变，ar2一起改变
ar1[2] = 9
print('ar1 = {0}, ar2 = {1}'.format(ar1, ar2))print('-' * 100)# copy方法生成数组及其数据的完整拷贝
ar3 = ar1.copy()
print('ar1 = {0}, ar3 = {1}'.format(ar1, ar3))
print('ar3 is ar1: ', ar3 is ar1)
ar1[0] = 9
print('ar1 = {0}, ar3 = {1}'.format(ar1, ar3))

打印结果：

ar1 = [0 1 2 3 4 5 6 7 8 9], ar2 = [0 1 2 3 4 5 6 7 8 9]
ar2 is ar1:  True
ar1 = [0 1 9 3 4 5 6 7 8 9], ar2 = [0 1 9 3 4 5 6 7 8 9]
----------------------------------------------------------------------------------------------------
ar1 = [0 1 9 3 4 5 6 7 8 9], ar3 = [0 1 9 3 4 5 6 7 8 9]
ar3 is ar1:  False
ar1 = [9 1 9 3 4 5 6 7 8 9], ar3 = [0 1 9 3 4 5 6 7 8 9]Process finished with exit code 0

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