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Follow up for problem "Populating Next Right Pointers in Each Node".
What if the given tree could be any binary tree? Would your previous solution still work?
Note:
- You may only use constant extra space.
For example,
Given the following binary tree,
1/ \2 3/ \ \4 5 7
After calling your function, the tree should look like:
1 -> NULL/ \2 -> 3 -> NULL/ \ \4-> 5 -> 7 -> NULL
/*** Definition for binary tree with next pointer.* struct TreeLinkNode {* int val;* TreeLinkNode *left, *right, *next;* TreeLinkNode(int x) : val(x), left(NULL), right(NULL), next(NULL) {}* };*/
class Solution {
public:void connect(TreeLinkNode *root) {while (root){TreeLinkNode * pre = nullptr;for (auto cur = root; cur; cur=cur->next){if (cur->left){if (pre == nullptr)root = cur->left;elsepre->next = cur->left;pre = cur->left;}if (cur->right){if (pre == nullptr)root = cur->right;elsepre->next = cur->right;pre = cur->right;}}if (pre == nullptr) //No next root found.break;}}
};
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