根据指定的参数截取URL然后获取指定参数的参数值

本文主要是介绍根据指定的参数截取URL然后获取指定参数的参数值，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

public static void main(String[] args) {String url = "https://web?id=1&page=12&name=吴彭正&param=111";String result  = urlSplit(url,"name");System.out.println(result);
}/*** 解析出url参数中的键值对* 如 "index.jsp?Action=del&id=123"，解析出Action:del,id:123存入map中* 根据参数名称获取参数后面的值* @param URL url地址* @return url请求参数部分* @author lzf*/
public static String urlSplit(String URL, String params) {String result = null ;Map<String, String> mapRequest = new HashMap<String, String>();String[] arrSplit = null;String strUrlParam = TruncateUrlPage(URL);if (strUrlParam == null) {return null;}arrSplit = strUrlParam.split("[&]");for (String strSplit : arrSplit) {String[] arrSplitEqual = null;arrSplitEqual = strSplit.split("[=]");//解析出键值if (arrSplitEqual.length > 1) {//正确解析mapRequest.put(arrSplitEqual[0], arrSplitEqual[1]);} else {if (arrSplitEqual[0] != "") {//只有参数没有值，不加入mapRequest.put(arrSplitEqual[0], "");}}}Iterator<Map.Entry<String, String>> it = mapRequest.entrySet().iterator();while (it.hasNext()) {Map.Entry<String, String> entry = it.next();if(entry.getKey().equals(params)){result =  entry.getValue();}}return result;
}private static String TruncateUrlPage(String strURL) {String strAllParam = null;String[] arrSplit = null;arrSplit = strURL.split("[?]");if (strURL.length() > 1) {if (arrSplit.length > 1) {for (int i = 1; i < arrSplit.length; i++) {strAllParam = arrSplit[i];}}}return strAllParam;
}

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