本文主要是介绍poj-3624-Charm Bracelet,希望对大家解决编程问题提供一定的参考价值,需要的开发者们随着小编来一起学习吧!
01背包问题
Description
Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weight Wi (1 ≤ Wi≤ 400), a 'desirability' factor Di (1 ≤ Di ≤ 100), and can be used at most once. Bessie can only support a charm bracelet whose weight is no more than M (1 ≤ M ≤ 12,880).
Given that weight limit as a constraint and a list of the charms with their weights and desirability rating, deduce the maximum possible sum of ratings.
Input
* Line 1: Two space-separated integers: N and M
* Lines 2..N+1: Line i+1 describes charm i with two space-separated integers: Wi and Di
Output
* Line 1: A single integer that is the greatest sum of charm desirabilities that can be achieved given the weight constraints
Sample Input
4 6 1 4 2 6 3 12 2 7
Sample Output
23
#include<iostream>
#include<cstring>
#define max1(a,b) a>b?a:b
using namespace std;
int a[12885],b[12885],c[12885];
int main()
{int n,m,i,j;while(cin>>n>>m){for(i=1;i<=n;i++)cin>>b[i]>>c[i];memset(a,0,sizeof(a));for(i=1;i<=n;i++)for(j=m;j>=b[i];j--)a[j]=max1(a[j],a[j-b[i]]+c[i]);cout<<a[m]<<endl;}return 0;
}
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